16t^2+22t+220=108

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Solution for 16t^2+22t+220=108 equation: 



16t^2+22t+220=108

We move all terms to the left:

16t^2+22t+220-(108)=0

We add all the numbers together, and all the variables

16t^2+22t+112=0

a = 16; b = 22; c = +112;
Δ = b2-4ac
Δ = 222-4·16·112
Δ = -6684
Delta is less than zero, so there is no solution for the equation

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